Results 1 to 6 of 6

Thread: CODE TAG Code Test

  1. #1
    Fuhrer, Vierte Reich DocAElstein's Avatar
    Join Date
    Aug 2014
    Posts
    9,454
    Rep Power
    10

    CODE TAG Code Test

    Code:
    '______________________________________________________________
    
    '______________________________________________________________
    '
    ' Slightly modified with lots of Comments
    Sub RickRothsteinsConcatenatingBalls()
    'NOTE: Change the ## A1 to the address of the top left cell of your
    'existing data and change the '### G1 to the address of the top left cell where you want the converted table to go to.
      Const ExistingTableAnyCellLocation As String = "A1" '##
      Const NewTableLHCornerLocation As String = "G1" '###
      
      Dim SourceTableRange As Range 'Give a name and allow all methods and properties of range object to it
      Set SourceTableRange = Range(ExistingTableAnyCellLocation).CurrentRegion ' Give this a specific Range. CurrentRegiuon Property applied to a cell returns a complete range incorporating that cell and any ranges that it either is in or touches
      Dim SourceTableRangeTableRowsCount As Byte ' For a small Table allow it to hve up to 255 Rows
      Let SourceTableRangeTableRowsCount = SourceTableRange.Rows.Count ' This returns the number of rows in the original table
    
      Dim FinalTableFirstColumnRange As Range
      Set FinalTableFirstColumnRange = Range(NewTableLHCornerLocation).Resize(SourceTableRangeTableRowsCount) ' Here the resize Property applied to the Range G1 (or Cell G1 here) returns a range increased by the row number, that is to say a range equal to the first column
      
      SourceTableRange.Columns(1).Resize(, 2).Copy Destination:=FinalTableFirstColumnRange ' This is one way of copying the first two columns of the original table to The final table
      FinalTableFirstColumnRange.Columns(2).NumberFormat = "@" ' This gives a format to the second column in the final Table
      
      'FinalTableFirstColumnRange.Offset(0, 1) = _
      'Evaluate("IF(ROW()," & SourceTableRange.Columns(2).Address & "&"" - ""&" & SourceTableRange.Columns(3).Address & "&"" - ""&" & SourceTableRange.Columns(4).Address & ")")
      'FinalTableFirstColumnRange.Offset(0, 1) = _
      'Evaluate("   " & SourceTableRange.Columns(2).Address & "&"" - ""&" & SourceTableRange.Columns(3).Address & "&"" - ""&" & SourceTableRange.Columns(4).Address & "")
       FinalTableFirstColumnRange.Offset(0, 1) = _
                    Evaluate("   " & SourceTableRange.Columns(2).Address & "     " & "&"" - ""&" & " " & SourceTableRange.Columns(3).Address & "  " & "&"" - ""&" & "" & SourceTableRange.Columns(4).Address & "")
      
      SourceTableRange.Columns(5).Copy Destination:=FinalTableFirstColumnRange.Offset(, 2) 'Column 5 of Original table is copied to column 3 of the Final table by setting the destination to 2 colums offset from the first column
      
      FinalTableFirstColumnRange.Cells(1, 0).Offset(0, 1).Value = "Numbers" ' The current heading in the second column is finally overwriten with "Numbers".  This is done here by putting the value"Numbers" in the cell which is offset by 1 column to the first cell in the Final Table First Column
    End Sub 'RickRothsteinsConcatenatingBalls()
    '
    ''_______________________________________________________________________________
    '__________________________________________________________________________________
    
    '______________________________________________________________
    
    ' Replacing the line I do not fully understand with a 3 line loop
    Sub RickRothsteinsConcatenatingBalls2()
      Dim j As Byte
    'NOTE: Change the ## A1 to the address of the top left cell of your
    'existing data and change the '### G1 to the address of the top left cell where you want the converted table to go to.
      Const ExistingTableAnyCellLocation As String = "A1" '##
      Const NewTableLHCornerLocation As String = "G1" '###
      
      Dim SourceTableRange As Range 'Give a name and allow all methods and properties of range object to it
      Set SourceTableRange = Range(ExistingTableAnyCellLocation).CurrentRegion ' Give this a specific Range. CurrentRegiuon Property applied to a cell returns a complete range incorporating that cell and any ranges that it either is in or touches
      Dim SourceTableRangeTableRowsCount As Byte ' For a small Table allow it to have up to 255 Rows
      Let SourceTableRangeTableRowsCount = SourceTableRange.Rows.Count ' This returns the number of rows in the original table
    
      Dim FinalTableFirstColumnRange As Range
      Set FinalTableFirstColumnRange = Range(NewTableLHCornerLocation).Resize(SourceTableRangeTableRowsCount) ' Here the resize Property applied to the Range G1 (or Cell G1 here) returns a range increased by the row number, that is to say a range equal to the first column
      
      SourceTableRange.Columns(1).Resize(, 2).Copy Destination:=FinalTableFirstColumnRange ' This is one way of copying the first two columns of the original table to The final table
      FinalTableFirstColumnRange.Columns(2).NumberFormat = "@" ' This gives a format to the second column in the final Table
      
        For j = 2 To SourceTableRangeTableRowsCount Step 1 ' For each column of data
        FinalTableFirstColumnRange.Cells(1, 1).Offset(j - 1, 1) = Evaluate("" & SourceTableRange.Cells(j, 2).Address & "" & "&"" - ""&" & "" & SourceTableRange.Cells(j, 3).Address & "" & "&"" - ""&" & "" & SourceTableRange.Cells(j, 4).Address & "") ' the evaluate fuction can be used in VBA to give the reults from a formula in a normal Excel Spreadsheet. Hier we use it simply to give the results of a formula something of the form  =B2 & " - " & C2 & " - " & D2. Just a convenient way of doung the concantenating. Further we here maks the addresses B2 C2 D2 variable in a loop. A very tricky syntax!!!
        Next j
      
      SourceTableRange.Columns(5).Copy Destination:=FinalTableFirstColumnRange.Offset(, 2) 'Column 5 of Original table is copied to column 3 of the Final table by setting the destination to 2 colums offset from the first column
      
      FinalTableFirstColumnRange.Cells(1, 0).Offset(0, 1).Value = "Numbers" ' The current heading in the second column is finally overwriten with "Numbers".  This is done here by putting the value"Numbers" in the cell which is offset by 1 column to the first cell in the Final Table First Column
    End Sub 'RickRothsteinsConcatenatingBalls2()
    '

  2. #2
    Fuhrer, Vierte Reich DocAElstein's Avatar
    Join Date
    Aug 2014
    Posts
    9,454
    Rep Power
    10

    Just a qick further test

    Code:
    '______________________________________________________________
    
    
    '______________________________________________________________
    '
    ' Slightly modified with lots of Comments
    Sub RickRothsteinsConcatenatingBalls()
    'NOTE: Change the ## A1 to the address of the top left cell of your
    'existing data and change the '### G1 to the address of the top left cell where you want the converted table to go to.
      Const ExistingTableAnyCellLocation As String = "A1" '##
      Const NewTableLHCornerLocation As String = "G1" '###
      
      Dim SourceTableRange As Range 'Give a name and allow all methods and properties of range object to it
      Set SourceTableRange = Range(ExistingTableAnyCellLocation).CurrentRegion ' Give this a specific Range. CurrentRegiuon Property applied to a cell returns a complete range incorporating that cell and any ranges that it either is in or touches
      Dim SourceTableRangeTableRowsCount As Byte ' For a small Table allow it to hve up to 255 Rows
      Let SourceTableRangeTableRowsCount = SourceTableRange.Rows.Count ' This returns the number of rows in the original table
    
    
      Dim FinalTableFirstColumnRange As Range
      Set FinalTableFirstColumnRange = Range(NewTableLHCornerLocation).Resize(SourceTableRangeTableRowsCount) ' Here the resize Property applied to the Range G1 (or Cell G1 here) returns a range increased by the row number, that is to say a range equal to the first column
      
      SourceTableRange.Columns(1).Resize(, 2).Copy Destination:=FinalTableFirstColumnRange ' This is one way of copying the first two columns of the original table to The final table
      FinalTableFirstColumnRange.Columns(2).NumberFormat = "@" ' This gives a format to the second column in the final Table
      
      'FinalTableFirstColumnRange.Offset(0, 1) = _
      'Evaluate("IF(ROW()," & SourceTableRange.Columns(2).Address & "&"" - ""&" & SourceTableRange.Columns(3).Address & "&"" - ""&" & SourceTableRange.Columns(4).Address & ")")
      'FinalTableFirstColumnRange.Offset(0, 1) = _
      'Evaluate("   " & SourceTableRange.Columns(2).Address & "&"" - ""&" & SourceTableRange.Columns(3).Address & "&"" - ""&" & SourceTableRange.Columns(4).Address & "")
       FinalTableFirstColumnRange.Offset(0, 1) = _
                    Evaluate("   " & SourceTableRange.Columns(2).Address & "     " & "&"" - ""&" & " " & SourceTableRange.Columns(3).Address & "  " & "&"" - ""&" & "" & SourceTableRange.Columns(4).Address & "")
      
      SourceTableRange.Columns(5).Copy Destination:=FinalTableFirstColumnRange.Offset(, 2) 'Column 5 of Original table is copied to column 3 of the Final table by setting the destination to 2 colums offset from the first column
      
      FinalTableFirstColumnRange.Cells(1, 0).Offset(0, 1).Value = "Numbers" ' The current heading in the second column is finally overwriten with "Numbers".  This is done here by putting the value"Numbers" in the cell which is offset by 1 column to the first cell in the Final Table First Column
    End Sub 'RickRothsteinsConcatenatingBalls()
    '
    ''_______________________________________________________________________________
    '__________________________________________________________________________________
    
    
    '______________________________________________________________
    
    
    ' Replacing the line I do not fully understand with a 3 line loop
    Sub RickRothsteinsConcatenatingBalls2()
      Dim j As Byte
    'NOTE: Change the ## A1 to the address of the top left cell of your
    'existing data and change the '### G1 to the address of the top left cell where you want the converted table to go to.
      Const ExistingTableAnyCellLocation As String = "A1" '##
      Const NewTableLHCornerLocation As String = "G1" '###
      
      Dim SourceTableRange As Range 'Give a name and allow all methods and properties of range object to it
      Set SourceTableRange = Range(ExistingTableAnyCellLocation).CurrentRegion ' Give this a specific Range. CurrentRegiuon Property applied to a cell returns a complete range incorporating that cell and any ranges that it either is in or touches
      Dim SourceTableRangeTableRowsCount As Byte ' For a small Table allow it to have up to 255 Rows
      Let SourceTableRangeTableRowsCount = SourceTableRange.Rows.Count ' This returns the number of rows in the original table
    
    
      Dim FinalTableFirstColumnRange As Range
      Set FinalTableFirstColumnRange = Range(NewTableLHCornerLocation).Resize(SourceTableRangeTableRowsCount) ' Here the resize Property applied to the Range G1 (or Cell G1 here) returns a range increased by the row number, that is to say a range equal to the first column
      
      SourceTableRange.Columns(1).Resize(, 2).Copy Destination:=FinalTableFirstColumnRange ' This is one way of copying the first two columns of the original table to The final table
      FinalTableFirstColumnRange.Columns(2).NumberFormat = "@" ' This gives a format to the second column in the final Table
      
        For j = 2 To SourceTableRangeTableRowsCount Step 1 ' For each column of data
        FinalTableFirstColumnRange.Cells(1, 1).Offset(j - 1, 1) = Evaluate("" & SourceTableRange.Cells(j, 2).Address & "" & "&"" - ""&" & "" & SourceTableRange.Cells(j, 3).Address & "" & "&"" - ""&" & "" & SourceTableRange.Cells(j, 4).Address & "") ' the evaluate fuction can be used in VBA to give the reults from a formula in a normal Excel Spreadsheet. Hier we use it simply to give the results of a formula something of the form  =B2 & " - " & C2 & " - " & D2. Just a convenient way of doung the concantenating. Further we here maks the addresses B2 C2 D2 variable in a loop. A very tricky syntax!!!
        Next j
      
      SourceTableRange.Columns(5).Copy Destination:=FinalTableFirstColumnRange.Offset(, 2) 'Column 5 of Original table is copied to column 3 of the Final table by setting the destination to 2 colums offset from the first column
      
      FinalTableFirstColumnRange.Cells(1, 0).Offset(0, 1).Value = "Numbers" ' The current heading in the second column is finally overwriten with "Numbers".  This is done here by putting the value"Numbers" in the cell which is offset by 1 column to the first cell in the Final Table First Column
    End Sub 'RickRothsteinsConcatenatingBalls2()

  3. #3
    Fuhrer, Vierte Reich DocAElstein's Avatar
    Join Date
    Aug 2014
    Posts
    9,454
    Rep Power
    10
    Great. I have the code in code tags in colour. Nice!
    (Thanks to Peter_SS at MrExcel for help in this one)

  4. #4
    Fuhrer, Vierte Reich DocAElstein's Avatar
    Join Date
    Aug 2014
    Posts
    9,454
    Rep Power
    10
    Code:
     '3) Part 3)--transfer range objects from dictionary to array of ranges in one go, typical Array assignment "One Liner" - The quick way to place data into an array is to dimension a variable ( for example rResults ) ....
     Dim rResults() As Variant '... As a Variant and then the "Let rResults  = " code line Using a variant allows BOTH .-1) for capturing Objects, text, numbers, blanks  errors etc. from those cells and also 2) allows rResults to be an array variable.....
     Let rResults() = dicLookupTable.Items() '... In this case it will also accept us quasi pre - defining as Array with the pair of parentheses rResults()
     'End part 3)--- NOTE: this gives automatically the 0 to ..   convention in rResults Array! and the output held in the Array is Variant type and is an OBJECT of the sort like a Range. (This compares with a similar code utilising An Array of Ranges rather than the MicrosoftScriptimeRuntimeDictionary. (In the Array of Ranges case we could Dim as Range or Variant here. - Important however in that case is that the Dynamic rResults() Array and the (in that Array of Ranges case non dynamic) arrIn() Array are of the same type. - Either both Range to return an Array of element Type Range or both Variant to Return an Array of element Type Of Objects of the Range Sort : - RoryA . You can only assign one array to another directly (i.e. without looping....... and the two arrays are the same type. http://www.excelforum.com/excel-new-users-basics/1058406-range-dimensioning-range-and-value-referencing-and-referring-to-arrays.html


    [CODE] Dim TempCell As Range: Set TempCell = wksLE.Cells(1, Columns.Count): Dim TempCellOffset As Long: Let TempCellOffset = 0 'We choose a cell (or through the later use of the offset a column) to use for Duplicate or Empty cells. We use the last column in the sheet. (This is genarally a good practice as it will not effect attempts with .End(XltoLeft) to find last column
    '2a) Part2a) Looping to put Range Objects in MRSD
    'For i = StartColumnTableOutput To LastColumnTableOutput Step 1
    For rws = sr To lr Step 1
    If wksLE.Cells(rws, 1).Value <> "" Then 'If cell is not empty then...
    If Not dicLookupTable.Exists(wksLE.Cells(rws, 1).Value) Then 'check that the unique value does not already exist. ##NOTE
    dicLookupTable.Add wksLE.Cells(rws, 1).Value, wksLE.Cells(rws, 1) 'it is easier to understand as well as kind of explicit the first argument does a CStr and the Second Takes anything
    Else 'If the key exists, that is to say we have a Range with a Duplicate value, we give the key a slightly modified (unique value) , still give the Range Object as an item, but make an indication, here by highlighting the cell in Pink
    Let TempCellOffset = TempCellOffset + 1
    Let TempCell.Offset(TempCellOffset, 0).Value = "Duplicate at " & rws & " | " & 1 & ""
    wksLE.Cells(rws, 1).Interior.Color = 10987519
    dicLookupTable.Add TempCell.Offset(TempCellOffset, 0).Value, wksLE.Cells(rws, 1) 'In case of duplicate we need a unique key, but we stillinclude the Duplicate Range
    End If
    Else 'Case fo an empty cell - inform of empty cell by writing message in that cell via the Tempory cell
    Let TempCellOffset = TempCellOffset + 1 'Go to next free tempory cell in tempory column
    Let TempCell.Offset(TempCellOffset, 0).Value = "Empty Cell at " & rws & " | " & 1 & ""
    dicLookupTable.Add TempCell.Offset(TempCellOffset, 0).Value, TempCell.Offset(TempCellOffset, 0)
    End If
    Next rws
    'Next i
    'End Part 2-----------------------------------------------------------

    '3) Part 3)--transfer range objects from dictionary to array of ranges in one go, typical Array assignment "One Liner" - The quick way to place data into an array is to dimension a variable ( for example rResults ) ....
    Dim rResults() As Variant '... As a Variant and then the "Let rResults = " code line Using a variant allows BOTH .-1) for capturing Objects, text, numbers, blanks errors etc. from those cells and also 2) allows rResults to be an array variable.....
    Let rResults() = dicLookupTable.Items() '... In this case it will also accept us quasi pre - defining as Array with the pair of parentheses rResults()
    'End part 3)--- NOTE: this gives automatically the 0 to .. convention in rResults Array! and the output held in the Array is Variant type and is an OBJECT of the sort like a Range. (This compares with a similar code utilising An Array of Ranges rather than the MicrosoftScriptimeRuntimeDictionary. (In the Array of Ranges case we could Dim as Range or Variant here. - Important however in that case is that the Dynamic rResults() Array and the (in that Array of Ranges case non dynamic) arrIn() Array are of the same type. - Either both Range to return an Array of element Type Range or both Variant to Return an Array of element Type Of Objects of the Range Sort : - RoryA . You can only assign one array to another directly (i.e. without looping....... and the two arrays are the same type. http://www.excelforum.com/excel-new-users-basics/1058406-range-dimensioning-range-and-value-referencing-and-referring-to-arrays.html

  5. #5
    Fuhrer, Vierte Reich DocAElstein's Avatar
    Join Date
    Aug 2014
    Posts
    9,454
    Rep Power
    10
    Kyle Extension test: Alt A

    Sub EvalutingQuotes()
    Dim v As Variant
    Let v = "3" ' Results in a Variant variable containing a string value "3"
    Let v = 3 ' Results in a Variant variable containing a Long Number 3 ( actually an Integer ? )


    Range("I1").Value = Evaluate("=" & Range("A1").Address & "") 'Explicit Version
    Range("I1").Value = Evaluate("" & Range("A1").Address & "") 'Implicit Default


    Range("I1").Value = Evaluate(" " & Range("A1").Address & " ") '


    Range("I1").Value = Evaluate(Range("A1").Address) 'Common but dangerous variation


    Dim strEval As String '
    strEval = "=A1" & "&" & "A1": Debug.Print strEval 'gives =A1&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 11


    strEval = "=A1" & "&"";""&" & "A1": Debug.Print strEval 'gives =A1&";"&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;1


    strEval = "=A1" & "&"";""": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;


    strEval = "=A1" & "&"";" & """": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;


    strEval = "=A1" & "&"";""""" & """": Debug.Print strEval 'gives =A1&";" ""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    strEval = "=A1" & "&"";"";""" & """": Debug.Print strEval 'gives=A1&";";""
    Range("I1").Value = Evaluate("" & strEval & "") 'error


    strEval = "=A1" & "&"";""" & """" & """": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error Gives 1;" !!!!!!!!


    strEval = "=A1" & "&"";""""""": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error Gives 1;" !!!!!!!!


    ' strEval = "=A1" & "&"";""""": Debug.Print strEval 'gives =A1&";""
    ' Range("I1").Value = Evaluate("" & strEval & "") 'error


    End Sub

    Not working today??

    ...................................

    Normal Code Tags

    Code:
    Sub EvalutingQuotes()
    Dim v As Variant
    Let v = "3" '  Results in a Variant variable containing a string value "3"
    Let v = 3 '    Results in a Variant variable containing a Long Number 3 ( actually an Integer ? )
    
    
    Range("I1").Value = Evaluate("=" & Range("A1").Address & "") 'Explicit Version
    Range("I1").Value = Evaluate("" & Range("A1").Address & "") 'Implicit Default
    
    
    Range("I1").Value = Evaluate("       " & Range("A1").Address & "       ") '
    
    
    Range("I1").Value = Evaluate(Range("A1").Address) 'Common but dangerous variation
    
    
    Dim strEval As String '
    strEval = "=A1" & "&" & "A1": Debug.Print strEval 'gives =A1&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 11
    
    
    strEval = "=A1" & "&"";""&" & "A1": Debug.Print strEval 'gives =A1&";"&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;1
    
    
    strEval = "=A1" & "&"";""": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
    
    
    strEval = "=A1" & "&"";" & """": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
    
    
    strEval = "=A1" & "&"";""""" & """": Debug.Print strEval 'gives =A1&";" ""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    strEval = "=A1" & "&"";"";""" & """": Debug.Print strEval 'gives=A1&";";""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    
    
    strEval = "=A1" & "&"";""" & """" & """": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error  Gives 1;"  !!!!!!!! :)
    
    
    strEval = "=A1" & "&"";""""""": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error  Gives 1;"  !!!!!!!! :)
    
    
            '    strEval = "=A1" & "&"";""""": Debug.Print strEval 'gives =A1&";""
            '    Range("I1").Value = Evaluate("" & strEval & "") 'error
    
    
    End Sub

    ...........................

    Old Alan Methd


    Code:
    Sub EvalutingQuotes()
    Dim v As Variant
    Let v = "3" '  Results in a Variant variable containing a string value "3"
    Let v = 3 '    Results in a Variant variable containing a Long Number 3 ( actually an Integer ? )
     
    Range("I1").Value = Evaluate("=" & Range("A1").Address & "") 'Explicit Version
    Range("I1").Value = Evaluate("" & Range("A1").Address & "") 'Implicit Default
     
    Range("I1").Value = Evaluate("       " & Range("A1").Address & "       ") '
     
    Range("I1").Value = Evaluate(Range("A1").Address) 'Common but dangerous variation
     
    Dim strEval As String '
    strEval = "=A1" & "&" & "A1": Debug.Print strEval 'gives =A1&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 11
     
    strEval = "=A1" & "&"";""&" & "A1": Debug.Print strEval 'gives =A1&";"&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;1
     
    strEval = "=A1" & "&"";""": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
     
    strEval = "=A1" & "&"";" & """": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
     
    strEval = "=A1" & "&"";""""" & """": Debug.Print strEval 'gives =A1&";" ""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    strEval = "=A1" & "&"";"";""" & """": Debug.Print strEval 'gives=A1&";";""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
     
    strEval = "=A1" & "&"";""" & """" & """": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error  Gives 1;"  !!!!!!!! :)
     
    strEval = "=A1" & "&"";""""""": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error  Gives 1;"  !!!!!!!! :)
     
            '    strEval = "=A1" & "&"";""""": Debug.Print strEval 'gives =A1&";""
            '    Range("I1").Value = Evaluate("" & strEval & "") 'error
     
    End Sub
    ............................
    EDIT : Try again...

    change my default
    From:

    General Settings
    Message Editor Interface
    Enhanced Interface - Full WYSIWYG Editing

    To:

    General Settings
    Message Editor Interface
    Standard Editor - Extra formatting controls

    Alt A

    Code:
    Sub EvalutingQuotes()
    Dim v As Variant
    Let v = "3" '  Results in a Variant variable containing a string value "3"
    Let v = 3 '    Results in a Variant variable containing a Long Number 3 ( actually an Integer ? )
    
    
    Range("I1").Value = Evaluate("=" & Range("A1").Address & "") 'Explicit Version
    Range("I1").Value = Evaluate("" & Range("A1").Address & "") 'Implicit Default
    
    
    Range("I1").Value = Evaluate("       " & Range("A1").Address & "       ") '
    
    
    Range("I1").Value = Evaluate(Range("A1").Address) 'Common but dangerous variation
    
    
    Dim strEval As String '
    strEval = "=A1" & "&" & "A1": Debug.Print strEval 'gives =A1&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 11
    
    
    strEval = "=A1" & "&"";""&" & "A1": Debug.Print strEval 'gives =A1&";"&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;1
    
    
    strEval = "=A1" & "&"";""": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
    
    
    strEval = "=A1" & "&"";" & """": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
    
    
    strEval = "=A1" & "&"";""""" & """": Debug.Print strEval 'gives =A1&";" ""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    strEval = "=A1" & "&"";"";""" & """": Debug.Print strEval 'gives=A1&";";""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    
    
    strEval = "=A1" & "&"";""" & """" & """": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error  Gives 1;"  !!!!!!!!
    
    
    strEval = "=A1" & "&"";""""""": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error  Gives 1;"  !!!!!!!!
    
    
            '    strEval = "=A1" & "&"";""""": Debug.Print strEval 'gives =A1&";""
            '    Range("I1").Value = Evaluate("" & strEval & "") 'error
    
    
    End Sub
    Last edited by DocAElstein; 09-16-2015 at 06:06 PM.

  6. #6
    Junior Member
    Join Date
    Oct 2012
    Posts
    4
    Rep Power
    0
    Code:
    Sub EvalutingQuotes()
    Dim v As Variant
    Let v = "3" ' Results in a Variant variable containing a string value "3"
    Let v = 3 ' Results in a Variant variable containing a Long Number 3 ( actually an Integer ? )
    
    
    Range("I1").Value = Evaluate("=" & Range("A1").Address & "") 'Explicit Version
    Range("I1").Value = Evaluate("" & Range("A1").Address & "") 'Implicit Default
    
    
    Range("I1").Value = Evaluate(" " & Range("A1").Address & " ") '
    
    
    Range("I1").Value = Evaluate(Range("A1").Address) 'Common but dangerous variation
    
    
    Dim strEval As String '
    strEval = "=A1" & "&" & "A1": Debug.Print strEval 'gives =A1&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 11
    
    
    strEval = "=A1" & "&"";""&" & "A1": Debug.Print strEval 'gives =A1&";"&A1
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;1
    
    
    strEval = "=A1" & "&"";""": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
    
    
    strEval = "=A1" & "&"";" & """": Debug.Print strEval 'gives =A1&";"
    Range("I1").Value = Evaluate("" & strEval & "") 'Gives 1;
    
    
    strEval = "=A1" & "&"";""""" & """": Debug.Print strEval 'gives =A1&";" ""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    strEval = "=A1" & "&"";"";""" & """": Debug.Print strEval 'gives=A1&";";""
    Range("I1").Value = Evaluate("" & strEval & "") 'error
    
    
    strEval = "=A1" & "&"";""" & """" & """": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error Gives 1;" !!!!!!!!
    
    
    strEval = "=A1" & "&"";""""""": Debug.Print strEval 'gives =A1&";"""
    Range("I1").Value = Evaluate("" & strEval & "") 'Did not error Gives 1;" !!!!!!!!
    
    
    ' strEval = "=A1" & "&"";""""": Debug.Print strEval 'gives =A1&";""
    ' Range("I1").Value = Evaluate("" & strEval & "") 'error
    
    
    End Sub

Similar Threads

  1. Replies: 5
    Last Post: 06-10-2019, 10:14 PM
  2. HTML Code Test --post8798
    By DocAElstein in forum Test Area
    Replies: 19
    Last Post: 06-17-2018, 03:02 PM
  3. Replies: 1
    Last Post: 08-23-2013, 06:33 PM
  4. Shorten VBA Code By Removing Redundant Superfluous Code
    By paul_pearson in forum Excel Help
    Replies: 2
    Last Post: 08-15-2013, 09:09 PM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •