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Thread: Validating PAN (Indian Format)

  1. #11
    Forum Guru Rick Rothstein's Avatar
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    I don't know this is a lot shorter than you were hoping for, but given you wanted complete error reporting, looping does not really help that much. I noticed you only tested the 4th character to be the letter "P" in your code and, since you said your code works fine, I restricted the check of the 4th character to only that letter. Note that I also added a check to see if the argument is too short or too long to be a proper entry. Here is the non-looping code I came up with...
    Code:
    Function IsPAN(S As String) As String
      If Len(S) < 10 Then
        IsPAN = "Too short!"
      ElseIf Len(S) > 10 Then
        IsPAN = "Too long!"
      Else
        If Mid(S, 1, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 1 is not text."
        If Mid(S, 2, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 2 is not text."
        If Mid(S, 3, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 3 is not text."
        If Mid(S, 4, 1) Like "[!Pp]" Then IsPAN = IsPAN & vbLf & "Character 4 is not the letter 'P'."
        If Mid(S, 5, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 5 is not text."
        If Mid(S, 6, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 6 is not a number."
        If Mid(S, 7, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 7 is not a number."
        If Mid(S, 8, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 8 is not a number."
        If Mid(S, 9, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 9 is not a number."
        If Mid(S, 10, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 10 is not text."
        If Len(IsPAN) Then
          IsPAN = Mid(IsPAN, 2)
        Else
          IsPAN = "OK"
        End If
      End If
    End Function
    In case you are interested, here is the same function using loops (among other things)...
    Code:
    Function IsPAN(S As String) As String
      Dim X As Long, PatternChar As String, Test As New Collection
      Const Pattern As String = "AAAPANNNNA"
      If Len(S) < 10 Then
        IsPAN = "Too short!"
      ElseIf Len(S) > 10 Then
        IsPAN = "Too long!"
      ElseIf Len(IsPAN) = 0 Then
        Test.Add "[A-Za-z]", "A"
        Test.Add "[Pp]", "P"
        Test.Add "#", "N"
        For X = 1 To Len(S)
          PatternChar = Test(Mid(Pattern, X, 1))
          If Not Mid(S, X, 1) Like PatternChar Then
            IsPAN = IsPAN & vbLf & "Character " & X & " is not " & Choose(InStr("APN", _
                    Mid(Pattern, X, 1)), "text.", "the letter ""P"".", "a number.")
          End If
        Next
        If Len(IsPAN) Then
          IsPAN = Mid(IsPAN, 2)
        Else
          IsPAN = "OK"
        End If
      End If
    End Function

  2. #12
    Administrator Admin's Avatar
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    Hi

    Thanks for posting the code. Since this particular forum is dedicated to tips and tricks, please do ask question in Excel Help
    Cheers !

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  3. #13
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    Thanks. Rilli good piece of work..:cool :

    Once again thanks a lot!!!


    Quote Originally Posted by Rick Rothstein View Post
    I don't know this is a lot shorter than you were hoping for, but given you wanted complete error reporting, looping does not really help that much. I noticed you only tested the 4th character to be the letter "P" in your code and, since you said your code works fine, I restricted the check of the 4th character to only that letter. Note that I also added a check to see if the argument is too short or too long to be a proper entry. Here is the non-looping code I came up with...
    Code:
    Function IsPAN(S As String) As String
      If Len(S) < 10 Then
        IsPAN = "Too short!"
      ElseIf Len(S) > 10 Then
        IsPAN = "Too long!"
      Else
        If Mid(S, 1, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 1 is not text."
        If Mid(S, 2, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 2 is not text."
        If Mid(S, 3, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 3 is not text."
        If Mid(S, 4, 1) Like "[!Pp]" Then IsPAN = IsPAN & vbLf & "Character 4 is not the letter 'P'."
        If Mid(S, 5, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 5 is not text."
        If Mid(S, 6, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 6 is not a number."
        If Mid(S, 7, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 7 is not a number."
        If Mid(S, 8, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 8 is not a number."
        If Mid(S, 9, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 9 is not a number."
        If Mid(S, 10, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 10 is not text."
        If Len(IsPAN) Then
          IsPAN = Mid(IsPAN, 2)
        Else
          IsPAN = "OK"
        End If
      End If
    End Function
    In case you are interested, here is the same function using loops (among other things)...
    Code:
    Function IsPAN(S As String) As String
      Dim X As Long, PatternChar As String, Test As New Collection
      Const Pattern As String = "AAAPANNNNA"
      If Len(S) < 10 Then
        IsPAN = "Too short!"
      ElseIf Len(S) > 10 Then
        IsPAN = "Too long!"
      ElseIf Len(IsPAN) = 0 Then
        Test.Add "[A-Za-z]", "A"
        Test.Add "[Pp]", "P"
        Test.Add "#", "N"
        For X = 1 To Len(S)
          PatternChar = Test(Mid(Pattern, X, 1))
          If Not Mid(S, X, 1) Like PatternChar Then
            IsPAN = IsPAN & vbLf & "Character " & X & " is not " & Choose(InStr("APN", _
                    Mid(Pattern, X, 1)), "text.", "the letter ""P"".", "a number.")
          End If
        Next
        If Len(IsPAN) Then
          IsPAN = Mid(IsPAN, 2)
        Else
          IsPAN = "OK"
        End If
      End If
    End Function

  4. #14
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    Ok, I agreed Sir.


    Rgds

    Quote Originally Posted by Admin View Post
    Hi

    Thanks for posting the code. Since this particular forum is dedicated to tips and tricks, please do ask question in Excel Help

  5. #15
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    Hello Sir,

    The above formula works fine.

    Thanks for the same. Would request you to let us know how to save the same in excel so that every time no need of pasting the above formula again ana again.

    Regards,
    Uday

  6. #16
    Forum Guru Rick Rothstein's Avatar
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    Quote Originally Posted by udaysdevadiga@gmail.com View Post
    The above formula works fine.

    Thanks for the same. Would request you to let us know how to save the same in excel so that every time no need of pasting the above formula again ana again.
    Do you really mean "formula" or are you referring to the VB code? There are 15 prior messages in this thread, some with formulas and some with VB code solutions... what is the number for the message containing the "formula" you are referring to (look for the number on the right side of the title bar for the message)?

  7. #17
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    Hello Sir,

    I am talking about the VB code. which is as below given bu you.

    Function IsPAN(S As String) As String
    If Len(S) < 10 Then
    IsPAN = "Too short!"
    ElseIf Len(S) > 10 Then
    IsPAN = "Too long!"
    Else
    If Mid(S, 1, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 1 is not text."
    If Mid(S, 2, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 2 is not text."
    If Mid(S, 3, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 3 is not text."
    If Mid(S, 4, 1) Like "[!Pp]" Then IsPAN = IsPAN & vbLf & "Character 4 is not the letter 'P'."
    If Mid(S, 5, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 5 is not text."
    If Mid(S, 6, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 6 is not a number."
    If Mid(S, 7, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 7 is not a number."
    If Mid(S, 8, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 8 is not a number."
    If Mid(S, 9, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 9 is not a number."
    If Mid(S, 10, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 10 is not text."
    If Len(IsPAN) Then
    IsPAN = Mid(IsPAN, 2)
    Else
    IsPAN = "OK"
    End If
    End If
    End Function

  8. #18
    Forum Guru Rick Rothstein's Avatar
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    Quote Originally Posted by udaysdevadiga@gmail.com View Post
    Hello Sir,

    I am talking about the VB code. which is as below given bu you.

    Function IsPAN(S As String) As String
    If Len(S) < 10 Then
    IsPAN = "Too short!"
    ElseIf Len(S) > 10 Then
    IsPAN = "Too long!"
    Else
    If Mid(S, 1, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 1 is not text."
    If Mid(S, 2, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 2 is not text."
    If Mid(S, 3, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 3 is not text."
    If Mid(S, 4, 1) Like "[!Pp]" Then IsPAN = IsPAN & vbLf & "Character 4 is not the letter 'P'."
    If Mid(S, 5, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 5 is not text."
    If Mid(S, 6, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 6 is not a number."
    If Mid(S, 7, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 7 is not a number."
    If Mid(S, 8, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 8 is not a number."
    If Mid(S, 9, 1) Like "[!0-9]" Then IsPAN = IsPAN & vbLf & "Character 9 is not a number."
    If Mid(S, 10, 1) Like "[!A-Za-z]" Then IsPAN = IsPAN & vbLf & "Character 10 is not text."
    If Len(IsPAN) Then
    IsPAN = Mid(IsPAN, 2)
    Else
    IsPAN = "OK"
    End If
    End If
    End Function
    Okay, I think the best way to do what I think you want is to create a template. Start a new workbook and put the above code in a module in that new workbook, then use Save As to save the workbook as an Excel Macro Enabled Template (give it a name you will recognize). Now, the next time you start a workbook that needs the PAN functionality, select that template instead of a blank workbook and the function will be in place ready-to-use.

  9. #19
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    Here is the Solution...

    =IF(AND(OR(MID(A1,4,1)={"P";"H";"B";"C";"L";"F";"A";"J";"G";"T"}),CODE(UPPER(MID(A1,{1,2,3,4,5},1)))>=65,CODE(UPPER(MID(A1,{1,2,3,4,5},1)))<=90,CODE(LOWER(MID(A1,{10},1)))>=97,CODE(LOWER(MID(A1,{10},1)))<=122,CODE(MID(A1,{6,7,8,9},1))>=49,CODE(MID(A1,{6,7,8,9},1))<=57,LEN(A1)=10),"VALID","INVALID")

  10. #20
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    Quote Originally Posted by in.vaibhav View Post
    Hi

    There is one more requirement, 4Th Character should be P for Individulas, C for Company & so on.

    So how can we check that & also whether we can give output with error instead of say True or False.

    EG. Length should be 10, First 5 character should be text, Next 6-9 character should be number, Last character should be text, 4th character should be either of P,H,F,A,T,B,L,J,G.

    Thanks & Regards
    Try This...

    =IF(AND(OR(MID(A1,4,1)={"P";"H";"B";"C";"L";"F";"A";"J";"G";"T"}),CODE(UPPER(MID(A1,{1,2,3,4,5},1)))>=65,CODE(UPPER(MID(A1,{1,2,3,4,5},1)))<=90,CODE(LOWER(MID(A1,{10},1)))>=97,CODE(LOWER(MID(A1,{10},1)))<=122,CODE(MID(A1,{6,7,8,9},1))>=49,CODE(MID(A1,{6,7,8,9},1))<=57,LEN(A1)=10),"VALID","INVALID")

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